jEasyUI 樹形菜單加載父/子節(jié)點

通常表示一個樹節(jié)點的方式就是在每一個節(jié)點存儲一個 parentid。這個也被稱為鄰接列表模型。直接加載這些數(shù)據(jù)到樹形菜單（Tree）是不允許的。但是我們可以在加載樹形菜單之前，把它轉(zhuǎn)換為標準標準的樹形菜單（Tree）數(shù)據(jù)格式。樹（Tree）插件提供一個 'loadFilter' 選項函數(shù)，它可以實現(xiàn)這個功能。它提供一個機會來改變?nèi)魏我粋€進入數(shù)據(jù)。本教程向您展示如何使用 'loadFilter' 函數(shù)加載父/子節(jié)點到樹形菜單（Tree）。

父/子節(jié)點數(shù)據(jù)

????[
????{"id":1,"parendId":0,"name":"Foods"},
????{"id":2,"parentId":1,"name":"Fruits"},
????{"id":3,"parentId":1,"name":"Vegetables"},
????{"id":4,"parentId":2,"name":"apple"},
????{"id":5,"parentId":2,"name":"orange"},
????{"id":6,"parentId":3,"name":"tomato"},
????{"id":7,"parentId":3,"name":"carrot"},
????{"id":8,"parentId":3,"name":"cabbage"},
????{"id":9,"parentId":3,"name":"potato"},
????{"id":10,"parentId":3,"name":"lettuce"}
????]

使用 'loadFilter' 創(chuàng)建樹形菜單（Tree）

????$('#tt').tree({
????????url: 'data/tree6_data.json',
????????loadFilter: function(rows){
????????????return convert(rows);
????????}
????});

轉(zhuǎn)換的實現(xiàn)

????function convert(rows){
????????function exists(rows, parentId){
????????????for(var i=0; i<rows.length; i++){
????????????????if (rows[i].id == parentId) return true;
????????????}
????????????return false;
????????}
????????
????????var nodes = [];
????????// get the top level nodes
????????for(var i=0; i<rows.length; i++){
????????????var row = rows[i];
????????????if (!exists(rows, row.parentId)){
????????????????nodes.push({
????????????????????id:row.id,
????????????????????text:row.name
????????????????});
????????????}
????????}
????????
????????var toDo = [];
????????for(var i=0; i<nodes.length; i++){
????????????toDo.push(nodes[i]);
????????}
????????while(toDo.length){
????????????var node = toDo.shift();????// the parent node
????????????// get the children nodes
????????????for(var i=0; i<rows.length; i++){
????????????????var row = rows[i];
????????????????if (row.parentId == node.id){
????????????????????var child = {id:row.id,text:row.name};
????????????????????if (node.children){
????????????????????????node.children.push(child);
????????????????????} else {
????????????????????????node.children = [child];
????????????????????}
????????????????????toDo.push(child);
????????????????}
????????????}
????????}
????????return nodes;
????}

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